How many moles of sodium chloride are formed by the interaction of sodium sulfate weighing 12.6 g with hydrochloric acid?

univerkov | March 1, 2021 | education

Let’s write the reaction equation:

Na2SO3 + 2 HCl → 2 NaCl + SO2 + H2O (sodium chloride, sulfur dioxide (sulfur (IV) oxide).

Let’s find the amount of sodium sulfite substance:

n (Na2SO3) = m (Na2SO3) / M (Na2SO3) = 12.6 g / 126 g / mol = 0.1 mol.

Let’s find the amount of sodium chloride substance according to the reaction equation:

n (NaCl) = 2 * n (Na2SO3) = 2 * 0.1 mol = 0.2 mol.

Answer: 0.2 mol.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.