How many moles of sodium chloride are formed by the interaction of sodium

How many moles of sodium chloride are formed by the interaction of sodium sulfite weighing 12.6 grams with hydrochloric acid?

Let’s execute the solution:

Let’s compose the equation of the process according to the condition of the problem:
Na2SO3 + 2HCl = 2NaCl + H2SO3 – ion exchange, sodium chloride, sulfurous acid was formed;

Calculations by formulas:
M (Na2SO3) = 125.8 g / mol.

Determine the amount of the original substance:
Y (Na2SO3) = m / M = 12.6 / 125.8 = 0.1 mol.

Proportion:
0.1 mol (Na2SO4) – X mol (NaCl);

-1 mol -2 mol hence, X mol (NaCl) = 0.1 * 2/1 = 0.2 mol.

Answer: Received sodium chloride in the amount of 0.2 mol.