How many oxygen atoms are there in 2.8 dm3 of nitric acid with a density of 1.64 g / cm3?

The mass of nitric acid is 2.8 l * 1000 * 1.64 g / cm3 = 4592 g.
The molar mass of HNO3 is 63 g / mol, which means that the indicated amount of nitric acid contains 3 * 6 * 10 ^ 23 * (4592: 63) =
1312 * 10 ^ 23 = 1.312 * 10 ^ 26 oxygen atoms.



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