How many oxygen molecules are needed to oxidize copper, which weighs 128 g?

Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:

Cu + ½ O2 = CuO ↑;

Let’s find the chemical amount of copper. To do this, we divide the weight of the available substance by the weight of 1 mole.

M Cu = 64 grams / mol;

N Cu = 128/64 = 2 mol;

To oxidize such an amount of copper, it is necessary to take 2 times less oxygen.

The number of oxygen molecules will be equal to Avogadro’s number and will be 6.022 x 10 ^ 23 molecules.