How many times are the impulses of a car with a mass of 1 ton moving at a speed of 9 km / h

How many times are the impulses of a car with a mass of 1 ton moving at a speed of 9 km / h and a gun projectile weighing 25 kg moving at a speed of 250 m / s differ.

The momentum of a body is equal to the product of the body’s mass by its velocity.
Hence:
P1 = m1 * V1; P2 = m2 * V2, where m1, m2 are the mass of the vehicle and the gun projectile (m1 = 1 t = 1000 kg, m2 = 25 kg); V1, V2 – vehicle and gun projectile speeds (V1 = 9 km / h = 9 * 1000/3600 m / s = 2.5 m / s, V2 = 250 m / s).
Then:
P1 = m1 * V1 = 1000 * 2.5 = 2500 kg * m / s.
P2 = m2 * V2 = 25 * 250 = 6250 kg * m / s.
P2 / P1 = 6250/2500 = 2.5.
Answer. The impulse of the gun projectile is 2.5 times greater than the impulse of the vehicle.