How many times are the resistances of two aluminum wires different if one of them has 6 times the length
| March 10, 2021 | education
How many times are the resistances of two aluminum wires different if one of them has 6 times the length and 3 times the cross-sectional area than the other?
Data: the ratio of the lengths of the indicated wires: l1 = 6l2; cross-sectional ratio: S1 = 3S2.
Resistance ratio: n = R1 / R2 = (ρa * l1 / S1) / (ρa * l2 / S2) = l1 * S2 / (l2 * S1) = 6l2 * S2 / (l2 * 3S2) = 6/3 = 2 R.
Answer: The resistances of the indicated aluminum wires differ by 2 times.
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