How many times do the areas of the pistons of a hydraulic press differ if, when acting on a small
| January 13, 2021 | education
How many times do the areas of the pistons of a hydraulic press differ if, when acting on a small piston with a force of 10 N, a force of 150 kN appears on a large piston?
To calculate the difference in the areas of the pistons of the specified hydraulic press, we use the formula: k = Sbp / Smp = Fbp / Fmp.
Variables: Fbp – the force that appeared on the larger piston (Fbp = 150 kN = 15 * 10^4 N); Fmp is the force on the small piston (Fmp = 10 N).
Calculation: k = Fbp / Fmp = 15 * 10^4/10 = 1.5 * 104 p.
Answer: The areas of the pistons of the specified hydraulic press differ by 1.5 * 10^4 times.
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