How many times do the heating losses of wires decrease when the voltage rises 100 times?
| July 6, 2021 | education
To estimate the decrease in losses for heating wires, we use the formula (we take into account that the power is constant): k = Qn / Qk = (In ^ 2 * R * t) / (Ik ^ 2 * R * t) = In ^ 2 / Ik ^ 2 = Uk ^ 2 / Un ^ 2 = (Uk / Un) ^ 2.
Variables: Uc (overvoltage) = 100Un (initial voltage).
Calculation: k = (Uc / Un) ^ 2 = (100Un / Un) ^ 2 = 10 ^ 4 times.
Answer: Losses for heating wires will decrease by 10 ^ 4 times.
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