How many times do the kinetic energies of bodies with masses of 5 kg and 10 kg differ

How many times do the kinetic energies of bodies with masses of 5 kg and 10 kg differ, if the speed of the second body is two times less than the first?

Kinetic energy of bodies:
Ek1 = (m1 * V1 ^ 2) / 2, where m1 is the mass of the first body (m1 = 5 kg), V1 is the speed of the first body (m / s).
Ek2 = (m2 * V2 ^ 2) / 2, where m2 is the mass of the second body (m2 = 10 kg), V2 is the speed of the second body (m / s).
Since the speed of the second body is two times less than the first, then V2 = 0.5V1.
Then:
Ek1 / Ek2 = ((m1 * V1 ^ 2) / 2) / ((m2 * (0.5V1) ^ 2)) / 2) = 5 / (10 * 0.5 ^ 2) = 5 / (10 * 0.25) = 2.
Answer: Kinetic energies differ by 2 times.