How many times does the number of radioactive nuclei decrease in a time equal to four half-lives?

To calculate the decrease in the number of radioactive nuclei for a given time, we use the formula: N = N0 * 2 ^ -t / T, whence we express: N0 / N = 1 / (2 ^ -t / T).

Variable relations: t (elapsed time) = 4T (half-life).

Let’s make a calculation: N0 / N = 1 / (2 ^ -t / T) = 1 / (2 ^ -4T / T) = 1 / (2-4) = 1 / 0.0625 = 16 p.

Answer: The number of radioactive nuclei, according to the calculation, will decrease 16 times.



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