How many times has the body’s momentum increased if its kinetic energy has doubled?

For a closed system, the kinetic energy is:
Ek = (m * V ^ 2) / 2, where m is the mass of the body, V is the speed of the body.
Body momentum can be calculated using the formula:
P = m * V.
Initial conditions:
Ek1 = (m * V1 ^ 2) / 2.
Increase in kinetic energy by 2 times:
Ek2 = (m * V2 ^ 2) / 2 = 2Ek1.
(m * V2 ^ 2) / 2 = 2 * (m * V1 ^ 2) / 2.
V2 ^ 2 = 2 * V1 ^ 2.
V2 / V1 = √2.
Body impulse change:
Р1 = m * V1, Р2 = m * V2.
P2 / P1 = m * V2 / (m * V1) = V2 / V1 = √2 = 1.41.
Answer: The momentum of the body will increase 1.41 times.