How many times has the volume of hydrogen containing the amount of substance ν = 0.4 mol

How many times has the volume of hydrogen containing the amount of substance ν = 0.4 mol increased during isothermal expansion, if the gas received the amount of heat Q = 800 J? Hydrogen temperature Т = 300 K.

To calculate the increase in the volume of taken hydrogen, we will use the formula: Q = A = ν * R * T * ln (Vk / Vn), from where we express: ln (Vk / Vn) = Q / (ν * R * T) and Vk / Vn = e (Q / (ν * R * T)).

Constants and variables: Q – heat received (Q = 800 J); ν is the amount of substance (ν = 0.4 mol); R – universal gas constant (R = 8.314 J / (K * mol)); T – constant abs. hydrogen temperature (T = 300 K).

Let’s make a calculation: Vc / Vn = e ^ (Q / (ν * R * T)) = 2.718 ^ (800 / (0.4 * 8.314 * 300)) = 2.23 p.

Answer: Hydrogen has increased its volume 2.23 times.



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