How many times is the area of a rectangle with sides of 9 cm and 4 cm larger than the area of a rectangle with sides of 6 cm and 2 cm.

The area of a rectangle is equal to the product of its two measurements of width and length
S = a * b
S1 = 9 * 4 = 36 cm ^ 2-area of the first rectangle
S2 = 6 * 2 = 12 cm ^ 2-area of the second rectangle
Now let’s find how many times the area of the first rectangle is greater than the area of the second:
S1 / S2 = 36/12 = 3 (times)
Answer: 3 times