How many times is the force of gravity acting on a load weighing 10 kg, which is lifted to a height equal

How many times is the force of gravity acting on a load weighing 10 kg, which is lifted to a height equal to the radius of the Earth, less than the force of gravity acting on the same load on its surface?

To find the ratio of the forces of attraction acting on the specified body at different heights, we apply the formula: k = Fп / Fв = (G * m * Mz / Rz ^ 2) / (G * m * Mz / (ht + Rz) ^ 2) = (ht + R3) ^ 2 / R3 ^ 2.

Variables: hт – body lifting height (hт = Rз).

Calculation: k = (ht + Rz) ^ 2 / Rz ^ 2 = (Rz + Rz) ^ 2 / Rz ^ 2 = 4Rz ^ 2 / Rz ^ 2 = 4 p.

Answer: After ascent to a height equal to the radius of the Earth, the indicated body will be affected by 4 times less gravitational force.