How many times is the force of internal friction acting on a ball that floats up in a liquid at a constant speed greater

How many times is the force of internal friction acting on a ball that floats up in a liquid at a constant speed greater than the force of gravity if the density of the liquid is three times the density of the ball’s material?

Given:
The ball is affected by 3 forces
F3 – force of resistance to movement (directed downward)
Ball gravity F1 = ro * V * g (downward)
Archimedean force F2 = ro * 1.4 * V * g (directed upwards)
It turns out, since the ball is moving upward at a constant speed, the resultant of all forces is zero
Decision :
F2 = F1 + F3
F3 = F2-F1 = ro * 1.4 * V * g-ro * V * g = ro * 0.4 * V * g
F1 / F3 = ro * V * g: ro * 0.4 * V * g = 1: 0.4 = 2.5
Answer: resistance force is 2.5 times less than gravity