How many times is the kinetic energy of a body weighing 7 kg greater than its potential energy

How many times is the kinetic energy of a body weighing 7 kg greater than its potential energy if it is at a height of 2 m, and its total mechanical energy is 500 J.

The potential energy of a body weighing 7 kg at a height of 2 m at g ≈ 10 m / s² is:
E = m * g * h = 7 * 10 * 2 = 140 J.
The total energy is 500 J, therefore, the kinetic energy is 500 – 140 = 360 J.
The ratio of kinetic and potential energies: 360/140 ≈ 2.6 times.
Answer: 2.6 times.



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