How many times is the linear speed of a point on the rim of a wheel with a radius of 0.6 m greater than the linear
| September 3, 2021 | education
How many times is the linear speed of a point on the rim of a wheel with a radius of 0.6 m greater than the linear speed of a point located 15 cm closer to the axis of rotation of the wheel?
R1 = 0.6 m.
R2 = R1 – 0.15 m.
V1 / V2 -?
The period of rotation T is the same for all points of the rim.
T = 2 * P * R1 / V1.
T = 2 * P * R2 / V2.
2 * P * R1 / V1 = 2 * P * R2 / V2.
R1 / V1 = R2 / V2.
R1 / V1 = (R1 – 0.15 m) / V2.
V1 * (R1 – 0.15) = R1 * V2.
V1 / V2 = R1 / (R1 – 0.15 m).
V1 / V2 = 0.6 m / (0.6 m – 0.15 m) = 1.33.
Answer: V1 / V2 = 1.33.
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