How many times is the mass of 5 liters of water more than the mass of the same volume of kerosene?

1) Calculate the mass of water:

m1 = ρ1 / V, where ρ1 is the density of water (ρ1 = 1000 kg / m3), V is the volume of water (V = 5 l = 5 dm3 = 5 * 10-3 m3).

m1 = ρ1 * V = 1000/5 * 10-3 = 5 kg.

Let’s calculate the mass of kerosene:

m2 = ρ2 / V, where ρ2 is the density of kerosene (ρ2 = 800 kg / m3).

m2 = ρ2 * V = 800/5 * 10-3 = 4 kg.

m2 / m1 = 5/4 = 1.25 times.

2) Since the volume of kerosene is equal to the volume of water:

m1 / m2 = ρ1 / ρ2 = 1000/800 = 1.25.

Answer: The mass of water is 1.25 times greater than the mass of kerosene.