How many times is the mass of a dust particle 10-8 grams greater than the mass of an air molecule?

univerkov | April 23, 2021 | education

Problem data: mp (dust grain mass) = 1 * 10 ^ -8 g (1 * 10 ^ -11 kg).

Reference values: Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1; according to the condition M (molar mass of air) = 29 * 10 ^ -3 kg / mol.

The ratio of the mass of a dust grain to the mass of an air molecule is determined by the formula: k = mp / mw = mp / (M / Na) = mp * Na / M.

Calculation: k = 1 * 10 ^ -11 * 6.02 * 10 ^ 23 / (29 * 10 ^ -3) = 207.6 * 10 ^ 12 times.

Answer: The mass of a dust particle is 207.6 * 10 ^ 12 times greater than the mass of one air molecule.

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