How many times more air (by mass) does the tank hold at 10 ° C than at 50 ° C, if the pressure remains unchanged?
| September 2, 2021 | education
To find the increase in air mass in the tank under consideration, we use the ratio: n = mn / mk = (P * V * M / (R * Tn)) / (P * V * M / (R * Tk)) = Tk / Tn.
Variables: Тк – reached temperature (Тк = 50 ºС = 323 К); Тн – initial temperature (Тн = 10 ºС = 283 К).
Let’s make a calculation: n = Tk / Tn = 323/283 = 1.141 p.
Answer: At 10 ° C, the reservoir under consideration holds 1.141 times more air.
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