# How many times must the distance between two charges be changed so that the force of interaction between

How many times must the distance between two charges be changed so that the force of interaction between them when immersed in kerosene is the same as in a vacuum? Dielectric constant of kerosene is 2.1

To calculate the required change in the distance between the two indicated charges, we use the equality: k * q1 * q2 / (εк * rк ^ 2) = F = k * q1 * q2 / (εв * rн ^ 2), whence we express: k = rн / rк = √ (εк / εв).

Constants: εк – dielectric constant of kerosene (according to the condition εк = 2.1); εв – dielectric constant of air (εв = 1).

Calculation: k = √ (εk / εv) = √ (2.1 / 1) = 1.45 p.

Answer: The distance between the two indicated charges must be reduced by 1.45 times.

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