How many times must the distance between two charges be changed so that the force of interaction between them when immersed in kerosene is the same as in a vacuum? Dielectric constant of kerosene is 2.1
To calculate the required change in the distance between the two indicated charges, we use the equality: k * q1 * q2 / (εк * rк ^ 2) = F = k * q1 * q2 / (εв * rн ^ 2), whence we express: k = rн / rк = √ (εк / εв).
Constants: εк – dielectric constant of kerosene (according to the condition εк = 2.1); εв – dielectric constant of air (εв = 1).
Calculation: k = √ (εk / εv) = √ (2.1 / 1) = 1.45 p.
Answer: The distance between the two indicated charges must be reduced by 1.45 times.
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