How many times the pressure at the bottom of the river at a depth of 15 m exceed the normal atmospheric pressure.

To find the ratio of the pressure at the bottom of the river and the normal atmospheric pressure, we use the formula: k = (ρw * g * h + Patm) / Patm.

Data: ρw – water density (for river water ρw = 10 ^ 3 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2); h – river depth (h = 15 m); Rathm – atmospheric pressure (we will assume Rathm ≈ 10 ^ 5 Pa).

Let’s perform the calculation: k = (ρw * g * h + Patm) / Patm = (10 ^ 3 * 10 * 15 + 10 ^ 5) / 10 ^ 5 = 2.5 p.

Answer: The pressure at the bottom of the river is 2.5 times higher than the atmospheric pressure.