How many times will the force of attraction to the Earth of the spacecraft

How many times will the force of attraction to the Earth of the spacecraft decrease as it moves away from the surface of the Earth at a distance equal to 5 Earth radii?

The force of attraction will decrease 36 times.
The law of universal gravitation is written as follows:
Ft = G * M * m / (R ^ 2)
Where Fт is the force of gravity or attraction;
M and m are the masses of two objects;
R is the distance between the centers of gravity of objects.
In the problem R = 5Rz + Rz = 6Rz;
Rz – the radius of the Earth
R ^ 2 = = (6Rs) ^ 2 = 36Rs.
Dividing the force of gravity on the surface by the force of gravity at a height of 5 Earth radii from the surface, and we get 36 times.



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