How many times will the perimeter and area of the rectangle increase if each side is increased 10 times?

Let’s denote the sides of the original rectangle a and b, then its perimeter is:
P1 = 2 * (a + b).
We write the area of the rectangle as:
S1 = a * b = ab.
According to the condition of the problem, the sides were increased by 10 times and they became 10a and 10b.
Find the perimeter and area of the new rectangle.
P2 = 2 * (10a + 10b) = 20 * (a + b);
S2 = 10a * 10b = 100ab.
Let’s compare the results obtained:
P2 / P1 = 20 * (a + b) / 2 * (a + b) = 10 (times);
S2 / S1 = 100ab / ab = 100 (times).
Answer: when the sides of a rectangle are increased by 10 times, its perimeter will increase by 10 times, and the area will increase by 100 times.