How many times will the period of oscillation of a spring pendulum decrease if a load weighing 1.6 kg

How many times will the period of oscillation of a spring pendulum decrease if a load weighing 1.6 kg is added to the same spring in a place of load weighing 4 kg

Initial data: m1 (initial mass of the weight of the spring pendulum) = 4 kg; m2 (mass of removable load) = 1.6 kg.

Since the oscillation period of a spring pendulum is calculated by the formula: T = 2Π * √ (m / k), the change in the oscillation period can be determined from the ratio: T1 / T2 = √m1 / √m2.

Let’s calculate: T1 / T2 = √4 / √1.6 = 1.58.

Answer: The period of oscillation of the spring pendulum will decrease by 1.58 times.