How many times will the pressure of a diatomic ideal gas in a vessel change
| February 6, 2021 | education
How many times will the pressure of a diatomic ideal gas in a vessel change if at the same temperature a third of the molecules disintegrates into atoms.
To calculate the change in pressure of the indicated diatomic gas, we use the ratio: Рк / Рн = nк * k * T / (nн * k * T) = nк / nн = (Nк / V) / (Nн / V) = Nк / Nн, whence we express: Рк = Nк * Рн / Nн.
The ratio of variables: Nc (final number of particles in the vessel) = 4/3 Nn (initial number of particles).
Let’s perform the calculation: Pk = Nk * Rn / Nn = (4/3 Nn) * Rn / Nn = 4/3 Rn.
Answer: The pressure of the indicated diatomic gas will increase by 4/3 times.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
