How many times will the pressure of a monatomic gas change as a result of a 3-fold decrease in its volume

univerkov | September 26, 2021 | education

How many times will the pressure of a monatomic gas change as a result of a 3-fold decrease in its volume and a 2-fold increase in the average kinetic energy of molecules?

To calculate the change in pressure of the indicated monatomic gas, we will use the ratio: k = Pк / Рн = (2/3 * n * Ekк) / (2/3 * n * Ekн) = (N / Vк * Ekк) / (N / Vн * Ekн) = (Vн * Ekк) / (Vк * Ekн).

Variable ratios: Vн (initial volume) = 3Vк (final volume); Ekk (final kinetic energy of molecules) = 2Ekн (initial energy).

Let’s perform the calculation: k = (Vn * Ekk) / (Vk * Ekn) = (3Vk * 2Ekn) / (Vk * Ekn) = 6 p.

Answer: The pressure of the indicated monatomic gas will increase 6 times.

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