How many times will the rate of a chemical reaction increase if the hydrogen concentration increases by 4 times

How many times will the rate of a chemical reaction increase if the hydrogen concentration increases by 4 times and the nitrogen concentration decreases by 5 times? This reaction takes place according to the equation 3H2 + N2 = 2NH3.

First, we write down what is the rate of the specified chemical reaction before the concentration of hydrogen and nitrogen was changed.
To do this, we will use the formula.
V = k [A] [B], where k is the rate constant, and A and B are the substances involved in the chemical reaction.
Now let’s compose the corresponding expression.
At the same time, pay attention to the equation 3H2 + N2 = 2NH3, which is given in the task.
V1 = k [H2] ³ × [N2].
Next, we write down what is the rate of the specified chemical reaction after the concentration of hydrogen and nitrogen has been changed.
At the same time, we draw attention to the fact that the hydrogen concentration will increase by 4 times, and the nitrogen concentration will decrease by 5 times.
V2 = k [4H2] ³ × ([N2]: 5).
Now let’s calculate.
V2 = k [4H2] ³ × ([N2]: 5) = k × 4³ × [H2] ³ × ([N2]: 5) = k × 64 × [H2] ³ × ([N2]: 5).
Now, in order to find out how many times the rate of a chemical reaction will increase, you should divide V2 by V1.
Next, we write down and calculate.
(k × 64 × [H2] ³ × [N2]: 5) / (k [H2] ³ × [N2]) = (64 × [N2]: 5) / ([N2]) = 64: 5 = 12 ,eight.
Answer: the speed of the chemical reaction will increase 12.8 times.