How many times will the rate of the direct reaction 2H2 + O2 → 2H2O increase with a 2-fold increase in pressure?

According to the law of mass action, the rate of this reaction will be expressed by the ratio:

v = k * C2 (H2) * C (O2);

When the total pressure is doubled, the concentrations of the components will also double. Then the ratio of the reaction rates can be expressed as:

v2 / v1 = (k * С22 (H2) * С2 (O2)) / (k * С12 (H2) * С1 (O2)) = k * (2 * С1 (H2)) 2 * (2 * С1 (O2 ))) / (k * С12 (H2) * С1 (O2)) = 8.

Answer: the reaction speed will increase by 8 times.