How many times will the volume of an air bubble rise at a constant temperature from a depth of 8 km to the surface
How many times will the volume of an air bubble rise at a constant temperature from a depth of 8 km to the surface increase? Atmospheric pressure is normal.
To calculate the increase in the volume of the specified air bubble when rising to the surface, we apply the formula: n = Vк / Vн = Рн / Рк = (Ратм + ρм.в. * g * h) / Рatm.
Data: Rathm – normal atmospheric pressure (we take Rathm ≈ 10 ^ 5 Pa); ρm.w. – the density of seawater (we take ρm.w. = 10 ^ 30 kg / m3); g – acceleration of gravity (g = 9.81 m / s2); h is the depth from which the indicated bubble emerged (h = 8 km = 8 * 10 ^ 3 m).
Calculation: n = (Ratm + ρm.v. * g * h) / Patm = (10 ^ 5 + 10 ^ 30 * 9.81 * 8 * 10 ^ 3) / 105 ≈ 809 r.
Answer: The volume of the indicated bubble will increase 809 times.