How many turns should the coil have in order for a voltage of 220 V to appear at its ends with a uniform

How many turns should the coil have in order for a voltage of 220 V to appear at its ends with a uniform increase in the magnetic flux through each turn from zero to 2 * 10 ^ -2 Vb for 5 * 10 ^ -3 s?

Data: Fn – initial magnetic flux (Fn = 0 Wb); Фк – achieved magnetic flux (Фк = 2 * 10 ^ -2 Vb); t is the duration of the growth of the magnetic flux (t = 5 * 10 ^ -3 s); U is the voltage generated (U = 220 V).

To find out the number of turns in the specified coil, consider the formula: U = ε = N * | (Фк – Фн) / t |, whence we express: N = U * t / (Фк – Фн).

Let’s perform the calculation: N = U * t / (Фк – Фн) = 220 * 5 * 10 ^ -3 / (2 * 10 ^ -2 – 0) = 55 turns.

Answer: The indicated coil must have 55 turns.