How many volumes of hydrogen are formed from the mass of 28 g of lithium in melted water?

To solve the problem, write down the equation:
m = 28 g. X l. -?
1.2Li + 2H2O = 2LiOH + H2 – OBP, hydrogen is released;
2. Calculations of molar masses:
M (Li) = 6.9 g / mol;
M (H2) = 2 g / mol.
4. Determine the number of moles of the starting material:
Y (Li) = m / M = 28 / 6.9 = 4 mol.
5. Proportion:
4 mol (Li) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 4 * 1/2 = 2 mol.
5. Find the volume of the product:
V (H2) = 2 * 22.4 = 44.8 liters.
Answer: during the reaction, 44.8 liters of hydrogen are released.