How many water molecules are there in a 0.2 g drop?
| December 27, 2020 | education
To calculate the number of molecules in the considered water drop, we will use the formula: N = m * Na / M.
Values of variables and constants: m is the mass of a drop of water (m = 0.2 g); ); Na – Avogadro’s number (Na = 6.02 * 10^23 mol-1); M is the molar mass of water (M ≈ 18 g / mol).
Calculation: N = m * Na / M = 0.2 * 6.02 / 18 = 66.9 * 10^20 molecules.
Answer: The considered drop of water contains 66.9 * 10^20 molecules.
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