How much 10% of sulfuric acid went to the reaction with ammonia if 4 g of ammonium sulfate was formed as a result?

Determine the chemical amount of ammonium sulfate. For this purpose, we divide its weight by its molar mass.

To do this, we divide the weight of the substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The amount of ammonium sulfate will be:

N (NH4) 2SO4 = 4/132 = 0.0303 mol;

To get this amount of salt, you need to take the same amount of sulfuric acid.

Let’s calculate its weight.

For this purpose, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

The weight of sulfuric acid will be:

m H2SO4 = 0.0303 x 98 = 2.97 grams;

The weight of the initial 10% sulfuric acid solution will be 2.97 / 0.1 = 29.7 grams;