How much acetylene can be completely burned in 400m O2?

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of oxygen.

To do this, we divide the volume of gas by the volume of 1 mole of ideal gas, which is 22.4 liters.

N O2 = 400,000 / 22.4 = 17,857 mol;

In such an amount of oxygen, 17 857/5 x 2 = 7143 mol of acetylene will burn.

Let’s calculate its volume by multiplying the amount of substance by the volume of 1 mol of gas.

V C2H2 = 7143 x 22.4 = 160,000 liters;