How much acetylene can be obtained from 150 g of calcium carbide containing 12% impurities?

The reaction for the synthesis of acetylene from calcium carbide is described by the following chemical reaction equation:

CaC2 + 2H2O = C2H2 + Ca (OH) 2;

From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.

Let’s calculate the available chemical amount of silicon carbide substance.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

N CaC2 = 150 x 0.88 / 64 = 2.063 mol;

The same amount of acetylene will be synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V C2H2 = 2.063 x 22.4 = 46.2 liters;