The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:
2C2H2 + 5O2 = 4CO2 + 2H2O;
2 moles of acetylene are reacted with 5 moles of oxygen. This will synthesize 4 moles of carbon dioxide and 2 moles of water.
Let’s find the available chemical amount of acetylene.
To do this, we divide its volume by the volume of 1 mole of acetylene.
N C2H2 = 67.1 / 22.4 = 3 mol;
The required amount of oxygen will be equal to:
N O2 = N C2H2 x 5/2 = 3 x 5/2 = 7.5 mol;
The oxygen volume will be:
V O2 = 7.5 x 22.4 = 168 liters;
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