How much air is required to burn 2.5 g of vanadium?

Given:
m (V) = 2.5 g
To find:
V (O2)
Decision:
4V + 5O2 = 2V2O5
n (V) = m / M = 2.5 g / 51 g / mol = 0.05 mol
n (V): n (O2) = 4: 5
n (O2) = 0.05 mol: 4 * 5 = 0.06 mol
V (O2) = n * Vm = 0.06 mol * 22.4 l / mol = 1.344 l
Answer: 1,344 l



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