How much air is required to burn 340 g of hydrogen sulfide?

1. Let’s write down the equation of hydrogen sulfide combustion:

2H2S + 3O2 = 2SO2 + 2H2O;

2.Calculate the chemical amount of H2S:

n (H2S) = m (H2S): M (H2S) = 340: 34 = 10 mol;

3. Determine the amount and volume of oxygen:

n (O2) = n (H2S) * 3: 2 = 10 * 3: 2 = 15 mol;

V (O2) = n (O2) * Vm = 15 * 22.4 = 336 l;

4.Knowing that the air contains 21% oxygen, we find the volume of required air:

V (air) = V (O2): ϕ (O2) = 336: 0.21 = 1600 l = 1.6 m ^ 3.

Answer: 1.6 m ^ 3.