How much air is required to burn a mixture of 5 liters of methane and 15 liters of acetylene?

univerkov | December 3, 2020 | education

The combustion of this mixture is oxygen, the content of which in the air is 21%
CH4 + 2O2 = CO2 + 2H2O
V (O2) = 2V (CH4) = 2 * 5 = 10 L
C2H2 + 2.5O2 = 2CO2 + H2O
V (O2) = 2.5V (C2H2) = 37.5
V (O2) total = 37.5 + 10 = 47.5 l
V (air) = V (O2) total \ 0.21 = 226 l
Sometimes in tasks the mass fraction of oxygen in the air is taken as 20%
then V (air) = 47.5 \ 0.2 = 237.5 l

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