How much air will it take to burn 1 kg of benzene?

Let’s compose the equation for the reaction of burning benzene:
2C6H6 + 15O2 = 12CO2 + 6H2O;

Let’s find the molecular weight of benzene:
12 * 6 + 6 = 78 g / mol;

Let’s find the amount of substance in benzene:
1000/78 = 12.821 mol;

There is a coefficient in front of oxygen, which is 7.5 times higher than before benzene. This means that the amount of substance in oxygen is 96.158 mol. Let’s find the volume of oxygen:
96.158 * 22.4 = 2153.94 liters;

The air contains 21% oxygen. Let’s find the volume of air:
2153.94 / 0.21 = 10256.857 liters;

Answer: The required air volume is 10256.857 liters.