How much air will it take to oxidize 164 g of copper? (air contains 21% oxygen)

univerkov | September 28, 2021 | education

Given:
m (Cu) = 164 g
φ (O2) = 21%

Find:
V (air) -?

1) 2Cu + O2 => 2CuO;
2) n (Cu) = m / M = 164/64 = 2.56 mol;
3) n (O2) = n (Cu) / 2 = 2.56 / 2 = 1.28 mol;
4) V (O2) = n * Vm = 1.28 * 22.4 = 28.67 l;
5) V (air) = V (O2) * 100% / φ (O2) = 28.67 * 100% / 21% = 136.5 liters.

Answer: The air volume is 136.5 liters.

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