How much Al contains 250 grams of aluminum oxide.

univerkov | January 17, 2021 | education

given:
m (Al2O3) = 250 g
to find:
m (Al)
decision:
4Al + 3O2 = 2Al2O3
n (Al2O3) = m: M = 250 g: 102 g / mol = 2.5 mol
from this it follows that n (Al) = 2.5 mol * 2 = 5 mol
m (Al) = n * M = 5 mol * 27 g / mol = 135 g
Answer: 135 g

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