How much aluminum chloride is required to prepare a 0.2 M solution with a volume of 0.5 liters?
December 29, 2020 | education
| Determine the required amount of substance to prepare the solution.
To do this, multiply the volume of the solution by its molar concentration.
In order to prepare such a solution, it is necessary to weigh and dissolve 0.2 x 0.5 = 0.1 mol of salt in water.
Let’s calculate the required weight of salt.
To do this, multiply the molar mass of the salt by the chemical amount of the substance.
M AlCl3 = 27 + 35.5 x 3 = 133.5 grams / mol;
m AlCl3 = 0.1 x 133.5 = 13.35 grams;
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