Let’s compose the reaction equation and arrange the coefficients:
2Al + 3S = Al2S3
Let’s make a proportion, including the amount of substance in moles and coefficients in front of aluminum and aluminum sulfide.
2 = 1 (row of coefficients)
x = 0.1 (string of moles)
x = 0.1 * 2/1 = 0.2 mol (amount of aluminum substance)
Answer: 0.2 mol of aluminum is required.
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