How much aluminum is required to replace chromium in 1.5 mol of its oxide 3?

univerkov | September 19, 2021 | education

Let’s make a chemical equation, not forgetting to put down the coefficients: Сr2O3 + 2Al = Al2O3 + 2Cr.
Using the equation, we make up the proportion: n (Cr2O3) / n (Al) = 1/2.
It turns out that the amount of aluminum is twice the amount of chromium.
We find the amount of aluminum substance: n (Al) = 1.5 * 2 = 3 mol.
Answer: n (Al) = 3 mol.

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