How much ammonia can be obtained by reacting 100 liters of nitrogen with hydrogen?

Let’s carry out the solution, write down the equation:
N2 + 3H2 = 2NH3 – reaction of the compound, ammonia was obtained;
M (N2) = 28 g / mol;
M (NH3) = 17 g / mol.
Determine the amount of mol of nitrogen:
1 mol of gas at n, y – 22.4 liters.
X mol (N2) – 100 liters. hence, X mol (N2) = 1 * 100 / 22.4 = 4.46 mol.
We make the proportion:
4.46 mol (N2) – X mol (NH3);
-1 mol -2 mol hence, X mol (NH3) = 4.46 * 2/1 = 8.928 mol.
Find the volume of ammonia:
V (NH3) = 8.928 * 22.4 = 199.98 liters.
Answer: in the course of the reaction, 199.98 liters of ammonia was released.