How much ammonia can be obtained from 100 liters of nitrogen and the required amount

How much ammonia can be obtained from 100 liters of nitrogen and the required amount (by volume) of hydrogen, if the loss of production is 25℅?

1. Let’s write down the reaction equation:

3H2 + N2 = 2NH3.

2. Find the amount of nitrogen and the yield of ammonia (Vm – molar volume, constant equal to 22.4 l / mol):

n (N2) = V (N2) / Vm = 100 L / 22.4 L / mol = 4.46 mol.

η (NH3) = 100% – ω (loss) = 100% – 25% = 75%

3. Using the equation, we find the theoretical amount of ammonia:

ntheor (NH3) = 0.5n (N2) = 2.23 mol.

nprak (NH3) = ntheor (NH3) * η (NH3) / 100% = 1.674 mol.

V (NH3) = nprak (NH3) * Vm = 1.674 mol * 22.4 l / mol = 37.5 l.

Answer: V (NH3) = 37.5 liters.