How much ammonia can be obtained from 42.8 g of ammonium chloride?
May 3, 2021 | education
| The decomposition reaction of ammonium chloride is described by the following chemical reaction equation:
NH4Cl = NH3 + HCl;
In this reaction, from one mole of ammonium chloride, one mole of ammonia and one mole of hydrochloric acid are formed.
Let’s find the available quantities of the substance.
M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;
N NH4Cl = 42.8 / 53.5 = 0.8 mol;
During the reaction, 0.8 mol of ammonia will be obtained. Let’s define its volume.
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
V NH3 = 0.8 x 22.4 = 19.92 liters;
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