How much ammonium can be obtained by reacting 2 mol of ammonium chloride with 1.5 mol of KOH?

Explanation: first, we compose the reaction equation, then it is necessary to find out who is in excess and who is in short supply. Since ammonium chloride and potassium hydroxide react in a ratio of 1: 1, NH4Cl is in excess, therefore, the calculation must be carried out according to KOH, according to the reaction, the amount of ammonia substance is equal to the amount of potassium hydroxide substance, therefore, it is also 1.5 mol.